A very simple solution for clockwise spiral matrix, self explanatory:
```
//spiral matrix let m=[   [ 1, 2, 3, 4, 5, 6], //0,0 to 0,5  [ 7, 8, 9,10,11,12],   [13,14,15,16,17,18],   [19,20,21,22,23,24] //3,0 to 3,5   ]; let top=0, left=0; let bottom=m.length-1, right=m[0].length-1; let direction="left"; // start from left towards right
while(true) { // First left to right → towards right     if(direction=="left")       {         for (let i=left;i<=right;i++)           console.log(m[top][i]);         top++; if (top>bottom) break; else         direction="down";       } // Second top to down ↓ : towards down     if(direction=="down")       {         for (let i=top;i<=bottom;i++)           console.log(m[i][right] );         right--; if(left>right) break; else         direction="right";       } //Third back from right to left ← towards left back      if(direction=="right")       {         for (let i=right;i>=left;i--)           console.log(m[bottom][i]);         bottom--; if (top>bottom) break; else         direction="up";       } // Fourth up ↑ up (from bottom to top) if(direction=="up")       {       for (let i=bottom; i>=top; i--)          console.log(m[i][left]); left++; if (left>right) break; else         direction="left";       }    } console.log("done") ```

Very simple, down to earth solution, self explanatory, clockwise spiral, written in JS but can be easily modified for any language
```
//spiral matrix let m=[   [ 1, 2, 3, 4, 5, 6], //0,0 to 0,5  [ 7, 8, 9,10,11,12],   [13,14,15,16,17,18],   [19,20,21,22,23,24] //3,0 to 3,5   ]; let top=0, left=0; let bottom=m.length-1, right=m[0].length-1; let direction="left"; // start from left towards right
while(true) { // First left to right → towards right     if(direction=="left")       {         for (let i=left;i<=right;i++)           console.log(m[top][i]);         top++; if (top>bottom) break; else         direction="down";       } // Second top to down ↓ : towards down     if(direction=="down")       {         for (let i=top;i<=bottom;i++)           console.log(m[i][right] );         right--; if(left>right) break; else         direction="right";       } //Third back from right to left ← towards left back      if(direction=="right")       {         for (let i=right;i>=left;i--)           console.log(m[bottom][i]);         bottom--; if (top>bottom) break; else         direction="up";       } // Fourth up ↑ up (from bottom to top) if(direction=="up")       {       for (let i=bottom;i>=top;i--)          console.log(m[i][left]); left++; if (left>right) break; else         direction="left";       }    } ```