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Score: 0.8378370404243469; Reported for: String similarity Open both answers

Possible Plagiarism

Reposted on 2025-04-18
by Vugar Abdullayev

Original Post

Original - Posted on 2025-04-18
by Vugar Abdullayev



            
Present in both answers; Present only in the new answer; Present only in the old answer;

ASsume we have `observableA` and `observableB`. Assume `observableA` and `observableB` already emitted a value so `zip` emits value. Now if `observableB `**emitted again** but `observableA` did not then `zip` does emit value. Because `zip` waits for `observableA` to **emit again**. In comparison, `combineLatest` would emit value with new `observableB` value and old `observableA` value .
Interesting Example.
``` // https://www.learnrxjs.io/learn-rxjs/operators/combination/zip import { fromEvent, zip } from 'rxjs'; import { map } from 'rxjs/operators';
const eventTime = eventName => fromEvent(document, eventName).pipe(map(() => new Date()));
const mouseClickDuration = zip( eventTime('mousedown'), eventTime('mouseup') ).pipe(map(([start, end]) => Math.abs(start.getTime() - end.getTime()))); ```
We have `mousedown`and `mouseup`. Assume `mousedown`and `mouseup`already emitted a value so `zip` emits value. Now if `mouseup` **emitted again** but `mousedown`did not then `zip` **does emit valu**e. Because `zip` waits for `mousedown`to **emit again**. In comparison, `combineLatest` would emit value with new `observableB` value and old `mousedown`value .
We have `observableA` and `observableB`. Assume `observableA` and `observableB` already emitted a value so `zip` emits value. Now if `observableB `**emitted again** but `observableA` did not then `zip` does emit value. Because `zip` waits for `observableA` to **emit again**. In comparison, `combineLatest` would emit value with new `observableB` value and old `observableA` value .
Interesting Example.
``` // https://www.learnrxjs.io/learn-rxjs/operators/combination/zip import { fromEvent, zip } from 'rxjs'; import { map } from 'rxjs/operators';
const eventTime = eventName => fromEvent(document, eventName).pipe(map(() => new Date()));
const mouseClickDuration = zip( eventTime('mousedown'), eventTime('mouseup') ).pipe(map(([start, end]) => Math.abs(start.getTime() - end.getTime()))); ```
We have `mousedown`and `mouseup`. Assume `mousedown`and `mouseup`already emitted a value so `zip` emits value. Now if `mouseup` **emitted again** but `mousedown`did not then `zip` **does emit valu**e. Because `zip` waits for `mousedown`to **emit again**. In comparison, `combineLatest` would emit value with new `observableB` value and old `mousedown`value .

        
Present in both answers; Present only in the new answer; Present only in the old answer;