Every class that doesn't explicitly extend another class implicitly extends java.lang.Object. So super() simply calls the no-arg constructor of Object.
Explicit call is unnecessary since the compiler would add it for you. You only need to add a super() call in a constructor when you want to invoke a superclass constructor with arguments.
so, result will be same whether you add super() constructor or not.

Every class that doesn't explicitly extend another class implicitly extends `java.lang.Object`. So `super()` simply calls the no-arg constructor of Object.
Note that this explicit call is unnecessary since the compiler would add it for you. You only need to add a `super()` call in a constructor when you want to invoke a superclass constructor with arguments.