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Detecting plagiarism made easy.

Score: 0.9058456013193804; Reported for: String similarity Open both answers

Possible Plagiarism

Plagiarized on 2021-05-19
by jahantaila

Original Post

Original - Posted on 2014-07-22
by fred



            
Present in both answers; Present only in the new answer; Present only in the old answer;

You can use `df.loc[i]`, where the row with index `i` will be what you specify it to be in the dataframe.
>>> import pandas as pd >>> from numpy.random import randint >>> df = pd.DataFrame(columns=['lib', 'qty1', 'qty2']) >>> for i in range(5): >>> df.loc[i] = ['name' + str(i)] + list(randint(10, size=2))
**should output**
>>> df lib qty1 qty2 0 name0 3 3 1 name1 2 4 2 name2 2 8 3 name3 2 1 4 name4 9 6

You can use `df.loc[i]`, where the row with index `i` will be what you specify it to be in the dataframe.

>>> import pandas as pd >>> from numpy.random import randint
>>> df = pd.DataFrame(columns=['lib', 'qty1', 'qty2']) >>> for i in range(5): >>> df.loc[i] = ['name' + str(i)] + list(randint(10, size=2)) >>> df lib qty1 qty2 0 name0 3 3 1 name1 2 4 2 name2 2 8 3 name3 2 1 4 name4 9 6


        
Present in both answers; Present only in the new answer; Present only in the old answer;