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Score: 1; Reported for: Exact paragraph match Open both answers

Possible Plagiarism

Plagiarized on 2021-02-02
by Rafael

Original Post

Original - Posted on 2015-04-28
by Demis



            
Present in both answers; Present only in the new answer; Present only in the old answer;

Save every iteration to png image file:
import matplotlib.pyplot as plt fig, ax = plt.subplots( nrows=1, ncols=1 ) # create figure & 1 axis ax.plot([0,1,2], [10,20,3]) fig.savefig('path/to/save/image/to.png') # save the figure to file plt.close(fig) # close the figure window

source: https://stackoverflow.com/a/9890599/12576990
Convert generated images to a video file:
import cv2 import os image_folder = 'images' video_name = 'video.avi' images = [img for img in os.listdir(image_folder) if img.endswith(".png")] frame = cv2.imread(os.path.join(image_folder, images[0])) height, width, layers = frame.shape video = cv2.VideoWriter(video_name, 0, 1, (width,height)) for image in images: video.write(cv2.imread(os.path.join(image_folder, image))) cv2.destroyAllWindows() video.release()
source: https://stackoverflow.com/a/44948030/12576990
As others have said, `plt.savefig()` or `fig1.savefig()` is indeed the way to save an image.
However I've found that in certain cases **the figure is always shown**. (eg. with Spyder having `plt.ion()`: interactive mode = On.) I work around this by forcing the closing of the figure window in my giant loop with `plt.close(figure_object)` (see [documentation][1]), so I don't have a million open figures during the loop:
import matplotlib.pyplot as plt fig, ax = plt.subplots( nrows=1, ncols=1 ) # create figure & 1 axis ax.plot([0,1,2], [10,20,3]) fig.savefig('path/to/save/image/to.png') # save the figure to file plt.close(fig) # close the figure window
You should be able to re-open the figure later if needed to with `fig.show()` (didn't test myself).

[1]: https://matplotlib.org/3.1.1/api/_as_gen/matplotlib.pyplot.close.html

        
Present in both answers; Present only in the new answer; Present only in the old answer;