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Score: 0.8008949160575867; Reported for: String similarity Open both answers

Possible Plagiarism

Plagiarized on 2019-10-03
by Shaho Soltani

Original Post

Original - Posted on 2016-06-02
by abhirathore2006



            
Present in both answers; Present only in the new answer; Present only in the old answer;

axios_humidity_data = () => { let s = true; if (s) { return new Promise((resolve, reject) => { try { axios .get( `http://35.204.247.157:8086/query?pretty=true&db=octobus&q=SELECT "humi" FROM "data" WHERE "assetMac" = 'F5:64:47:40:2E:03'` ) .then(response => { const data = response.data.results[0].series[0].values; let date = []; let humidity = []; data.forEach(chart_item => { date.push(chart_item[0]); humidity.push(chart_item[1]); s = false; return; }); this.setState({ humidity_data: { labels: date, datasets: [ { label: "Humidity %", data: humidity, backgroundColor: [ "rgba(255,105,145,0.1)", "rgba(155,100,210,0.1)", "rgba(90,178,255,0.1)", "rgba(240,134,67,0.1)", "rgba(120,120,120,0.1)", "rgba(250,55,197,0.1)" ] } ] } }); // console.log(data); resolve(data); s = false; return; }); } catch (err) { reject(err); } }); } else { console.log("data is not available"); s = false; return; } };
This can be done in multple ways.
1. As suggested above, before `return` store all elements in the array 2. Loop inside `return`
Method 1

let container =[]; let arr = [1,2,3] //can be anything array, object arr.forEach((val,index)=>{ container.push(<div key={index}> val </div>) /** * 1. All loop generated elements require a key * 2. only one parent element can be placed in Array * e.g. container.push(<div key={index}> val </div> <div> this will throw error </div> ) **/ }); return ( <div> <div>any things goes here</div> <div>{container}</div> </div> ) Method 2 return( <div> <div>any things goes here</div> <div> {(()=>{ let container =[]; let arr = [1,2,3] //can be anything array, object arr.forEach((val,index)=>{ container.push(<div key={index}> val </div>) }); return container; })()} </div> </div> )

        
Present in both answers; Present only in the new answer; Present only in the old answer;