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Score: 0.8023794293403625; Reported for: String similarity Open both answers

Possible Plagiarism

Plagiarized on 2019-09-13
by David S

Original Post

Original - Posted on 2009-05-20
by Jon Skeet



            
Present in both answers; Present only in the new answer; Present only in the old answer;

As I understand from running your code, you want to enter a string as argument and just parse it and print it, as simple as that right?
the code isn't compiling due to a typo in line:
data[i]=(char *)malloc(sizeof(char)*l)+1);
After fixing it to:
data[i]=(char *)malloc(sizeof(char)*l+1);
The output of the code is, for "hello this is string":
hello this is string ...Program finished with exit code 0
If you still have segmentation error please post more information
Like other answerers, I'd definitely *prefer* to put the loops in a different method, at which point you can just return to stop iterating completely. This answer just shows how the requirements in the question can be met.
You can use `break` with a label for the outer loop. For example:
public class Test { public static void main(String[] args) { outerloop: for (int i=0; i < 5; i++) { for (int j=0; j < 5; j++) { if (i * j > 6) { System.out.println("Breaking"); break outerloop; } System.out.println(i + " " + j); } } System.out.println("Done"); } }
This prints:
0 0 0 1 0 2 0 3 0 4 1 0 1 1 1 2 1 3 1 4 2 0 2 1 2 2 2 3 Breaking Done


        
Present in both answers; Present only in the new answer; Present only in the old answer;