subscribe(...) will return a Subscription
Try to edit your code, make method return a Subscription like this
public Subscription getAuthObservable() {
return NetworkClient.getRetrofit().create(NetworkInterface.class)
.getAuthDetails("application/x-www-form-urlencoded",
new AuthRequestDetails().getAuthRequestDetails())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(new Observer<Response<Void>>() {
@Override
public void onSubscribe(Disposable d) {
}
@Override
public void onNext(Response<Void> voidResponse) {
String access_token_received = voidResponse.headers().get("access_token");
}
@Override
public void onError(Throwable e) {
}
@Override
public void onComplete() {
}
});
}
Yes, you can use flatmap for this exact purpose. See the below example (Assuming your service A returns `Observable<FooA>` and service B returns `Observable<FooB>`)
api.serviceA()
.flatMap(new Func1<FooA, Observable<FooB>>() {
@Override
public Observable<FooB> call(FooA fooA) {
// code to save data from service A to db
// call service B
return api.serviceB();
}
})
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(new Subscriber<FooB>() {
@Override
public void onCompleted() {
}
@Override
public void onError(Throwable e) {
}
@Override
public void onNext(FooB fooB) {
// code to save data from service B to db
}
});
