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Score: 2; Reported for: String similarity, Exact paragraph match Open both answers

Possible Plagiarism

Reposted on 2023-11-18
by Makeman

Original Post

Original - Posted on 2023-11-18
by Makeman



            
Present in both answers; Present only in the new answer; Present only in the old answer;

Please, consider this patterns
... x^3 = x*x*x x^2 = x*x x^1 = x x^0 = ????? x^-1 = ????? ...
... x^3 = 1*x*x*x x^2 = 1*x*x x^1 = 1*x x^0 = 1 x^-1 = 1/x x^-2 = 1/x/x x^-3 = 1/x/x/x ...
A simple traditional definition of `pow` function means **how many times we multiply a number by self**.
But in more strict sense `pow` function means **how many times we multiply or divide the one by a number**.
By this reason `x^0 = 1` => `0^0 = (-1)^0 = 1` too.
In [a more general case][1] the `seed` may be any number.
static double Pow(double x, int pow, double seed = 1d) { var value = seed; if (pow < 0) for (var i = 0; i > pow; i--) value /= x; else for (var i = 0; i < pow; i++) value *= x; return value; }

[1]: https://sharplab.io/#v2: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
Please, consider this patterns
... x^3 = x*x*x x^2 = x*x x^1 = x x^0 = ????? x^-1 = ????? ...
... x^3 = 1*x*x*x x^2 = 1*x*x x^1 = 1*x x^0 = 1 x^-1 = 1/x x^-2 = 1/x/x x^-3 = 1/x/x/x ...
A simple traditional definition of `pow` function means **how many times we multiply a number by self**.
But in more strict sense `pow` function means **how many times we multiply or divide the one by a number**.
By this reason `x^0 = 1` => `0^0 = (-1)^0 = 1` too.
In [a more general case][1] the `seed` may be any number.
static double Pow(double x, int pow, double seed = 1d) { var value = seed; if (pow < 0) for (var i = 0; i > pow; i--) value /= x; else for (var i = 0; i < pow; i++) value *= x; return value; }

[1]: https://sharplab.io/#v2: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

        
Present in both answers; Present only in the new answer; Present only in the old answer;