Present in both answers;Present only in the new answer;Present only in the old answer;
`$cache_disqus` is defined outside your function, and is therefore not accessible within the function. Check out the PHP documentation on variable scope.
`$cache_disqus` is defined **outside** your function, and is therefore not accessible within the function. Check out the [PHP documentation on variable scope](http://www.php.net/manual/en/language.variables.scope.php).
Present in both answers;Present only in the new answer;Present only in the old answer;
