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Score: 1.8386959433555603; Reported for: String similarity, Exact paragraph match Open both answers

Possible Plagiarism

Reposted on 2021-11-17
by Jahid Hasan

Original Post

Original - Posted on 2021-11-16
by Jahid Hasan



            
Present in both answers; Present only in the new answer; Present only in the old answer;

Try This One:
``` <?php $paged = ( get_query_var( 'paged' ) ) ? absint( get_query_var( 'paged' ) ) : 1; $args = array( 'post_type' => 'connazionali', 'post_status' => 'publish', 'posts_per_page' => 10, 'order' => 'ASC', 'paged' => $paged, ); $arr_posts = new WP_Query( $args );
if ( $arr_posts->have_posts() ) : while ( $arr_posts->have_posts() ) : $arr_posts->the_post(); ?>
<h3 class="entry-title"><?php the_title(); ?></h3>
<?php endwhile; endif; ?>

<div class="page-pagination"> <?php
$arr_posts_page = $arr_posts->max_num_pages; if ($arr_posts_page > 1){
$current_page = max(1, get_query_var('paged'));
echo paginate_links(array( 'base' => get_pagenum_link(1) . '%_%', 'format' => 'page/%#%', 'current' => $current_page, 'total' => $arr_posts_page, 'prev_text' => __('<'), 'next_text' => __('>'), )); } ?> </div>
You can modify this code :
``` <?php $paged = ( get_query_var( 'paged' ) ) ? absint( get_query_var( 'paged' ) ) : 1; $args = array( 'post_type' => 'post', 'post_status' => 'publish', 'posts_per_page' => 10, 'order' => 'ASC', 'paged' => $paged, ); $arr_posts = new WP_Query( $args );
if ( $arr_posts->have_posts() ) : while ( $arr_posts->have_posts() ) : $arr_posts->the_post(); ?>
<h3 class="entry-title"><?php the_title(); ?></h3>
<?php endwhile; endif; ?>

<div class="pagepagination"> <?php
$arr_posts_page = $arr_posts->max_num_pages; if ($arr_posts_page > 1){
$current_page = max(1, get_query_var('paged'));
echo paginate_links(array( 'base' => get_pagenum_link(1) . '%_%', 'format' => 'page/%#%', 'current' => $current_page, 'total' => $arr_posts_page, 'prev_text' => __('<'), 'next_text' => __('>'), )); } ?> </div>

        
Present in both answers; Present only in the new answer; Present only in the old answer;